(3*6/2)v+10=3^3+10

Solution for (3*6/2)v+10=3^3+10 equation:

(3*6/2)v+10=3^3+10

We move all terms to the left:

(3*6/2)v+10-(3^3+10)=0


Domain of the equation: 2)v!=0

v!=0/1

v!=0

v∈R


We add all the numbers together, and all the variables

(+3*6/2)v+10-(3^3+10)=0

We add all the numbers together, and all the variables

(+3*6/2)v-27=0

We multiply parentheses

18v^2-27=0

a = 18; b = 0; c = -27;
Δ = b2-4ac
Δ = 02-4·18·(-27)
Δ = 1944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1944}=\sqrt{324*6}=\sqrt{324}*\sqrt{6}=18\sqrt{6}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{6}}{2*18}=\frac{0-18\sqrt{6}}{36}
=-\frac{18\sqrt{6}}{36}
=-\frac{\sqrt{6}}{2}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{6}}{2*18}=\frac{0+18\sqrt{6}}{36}
=\frac{18\sqrt{6}}{36}
=\frac{\sqrt{6}}{2}
$